Answer
$23+10i$.
Work Step by Step
The given expression is
$=(8+9i)(2-i)-(1-i)(1+i)$
$=(16-8i+18i-9i^2)-(1^2-i^2)$
Use $i^2=-1$.
$=(16-8i+18i+9)-(1+1)$
Clear the parentheses.
$=16-8i+18i+9-1-1$
Add like terms.
$=23+10i$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 570: 102
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