Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 570: 42

Answer

$16-28i $.

Work Step by Step

The given expression is $=(8-4i)(3-2i)$ Use the FOIL method. $=(8)\cdot(3)+(8)\cdot(-2i) + (-4i)\cdot(3)+(-4i)\cdot(-2i)$ Simplify. $=24-16i -12i+8i^2$ Use $i^2=-1$ $=24-16i -12i-8$ Add like terms. $=16-28i $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.