Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 31

Answer

$a(ab-7c)(ab+7c)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $x^2-y^2=(x-y)(x+y)$ Factor out the greatest common factor, $a$, to obtain: $=a(a^2b^2-49c^2) \\=a[(ab)^2-(7c)^2]$ The binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $x=ab$ and $b=7c$ to obtain: $=a(ab-7c)(ab+7c)$
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