Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 371: 3

Answer

$(3x-5)(3x+5)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ The given binomial can be written as: $=(3x)^2-5^2$ This binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $a=3x$ and $b=5$ to obtain: $=(3x-5)(3x+5)$
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