Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 371: 18

Answer

$(a-b+3)(a+b-3)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $x^2-y^2=(x-y)(x+y)$ Factor the given difference of two squares using the formula above with $x=a$ and $y=b-3$ to obtain: $=[a-(b-3)][a+(b-3)] \\=(a-b+3)(a+b-3)$
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