Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 15

Answer

$(x-y-3)(x+y-3)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ Factor the given difference of two squares using the formula above with $a=x-3$ and $b=y$ to obtain: $=[(x-3)-y][(x-3)+y] \\=(x-3-y)(x-3+y) \\=(x-y-3)(x+y-3)$
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