Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 22

Answer

$(2-b^n)(2+b^n)$

Work Step by Step

RECALL: A difference of two squares can be factored using the formula: $x^2-y^2=(x-y)(x+y)$ The given binomial can be written as: $=(2)^2-(b^n)^2$ This binomial is a difference of two squares. Factor the given difference of two squares using the formula above with $x=2$ and $y=b^n$ to obtain: $=(2-b^n)(2+b^n)$
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