## Intermediate Algebra (6th Edition)

We are given that $log_{b}3=.5$ and that $log_{b}5=.7$. The power property of logarithms tells us that $log_{b}x^{r}=r log_{b}x$ (where x and b are positive real numbers, $b\ne1$, and r is a real number). Therefore, $log_{b}\sqrt 5= log_{b}5^{\frac{1}{2}}=\frac{1}{2}log_{b}5=\frac{1}{2}\times .7=.35$.