Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.6 - Properties of Logarithms - Exercise Set: 53

Answer

1.2

Work Step by Step

We are given that $log_{b}3=.5$ and that $ log_{b}5=.7$. The product property of logarithms tells us that $log_{b}xy=log_{b}x+log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$). Therefore, $log_{b}15= log_{b}3+ log_{b}5=.5+.7=1.2$.
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