## Intermediate Algebra (6th Edition)

$3log_{2}y+log_{2}z$
The product property of logarithms tells us that $log_{b}xy=log_{b}x+log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$). Therefore, $log_{2}y^{3}z= log_{2}y^{3}+log_{2}z$. The power property of logarithms tells us that $log_{b}x^{r}=r log_{b}x$ (where x and b are positive real numbers, $b\ne1$, and r is a real number). Therefore, $log_{2}y^{3}+log_{2}z= 3log_{2}y+log_{2}z$.