## Intermediate Algebra (6th Edition)

We are given that $log_{b}3=.5$ and that $log_{b}5=.7$. The quotient property of logarithms tells us that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$). Therefore, $log_{b}\frac{5}{3}= log_{b}5- log_{b}3=.7-.5=.2$.