Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 67

Answer

$x=\left\{ 8,64 \right\}$

Work Step by Step

Let $z=x^{1/3}$. Then the given expression, $ x^{2/3}-6x^{1/3}=-8 ,$ is equivalent to \begin{array}{l}\require{cancel} z^2-6z=-8 \\\\ z^2-6z+8=0 \\\\ (z-4)(z-2)=0 \\\\ z=\{2,4\} .\end{array} Since $z=x^{1/3}$, then if $z=2$, \begin{array}{l}\require{cancel} 2=x^{\frac{1}{3}} \\\\ (2)^3=(x^{\frac{1}{3}})^3 \\\\ 8=x .\end{array} Since $z=x^{1/3}$, then if $z=4$, \begin{array}{l}\require{cancel} 4=x^{\frac{1}{3}} \\\\ (4)^3=(x^{\frac{1}{3}})^3 \\\\ 64=x .\end{array} Hence, $ x=\left\{ 8,64 \right\} .$
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