Answer
$y=-7/9*(x+3)^2+7$
Work Step by Step
$y=a(x-h)^2+k$
$a=-7/9$
Vertex is $(-3,7)$
The vertex of a parabola is of the form $(h,k)$.
$y=a(x-h)^2+k$
$y=a(x+3)^2+7$
$a=-7/9$
$y=a(x+3)^2+7$
$y=-7/9*(x+3)^2+7$
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