Answer
The vertex is labeled with its coordinates, and the green line is the axis of symmetry.
Work Step by Step
$f(x)=x^2-4$
$a=1$, $b=0$, $c=-4$
The axis of symmetry is at $x=-b/2a$
$x=-b/2a$
$x=-0/2*1$
$x=-0/2$
$x=0$
The vertex is at $x=0$
$f(x)=x^2-4$
$f(0)=0^2-4$
$f(0)=0-4$
$f(0)=-4$
$(0, -4)$ is the vertex.