Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 54a

Answer

.4 seconds and 7.1 seconds

Work Step by Step

$h(t) =-16t^2+120t+300$ $h(t)=350$ $350=-16t^2+120t+300$ $350-350=-16t^2+120t+300-350$ $0=-16t^2+120t-50$ $0=(-16t^2+120t-50)/2$ $0=-8t^2+60t-25$ $a=-8$, $b=60$, $c=-25$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-60±\sqrt {60^2-4*(-8)*-25})/2*-8$ $x=(-60±\sqrt {3600-800})/-16$ $x=(-60±\sqrt {2800})/-16$ $x=(-60±\sqrt {4*7*100})/-16$ $x=(-60±20\sqrt 7)/-16$ $x=(-60±20*2.645)/-16$ $x=(-60±52.915)/-16$ $x=(-60+52.915)/-16$ $x=-7.085/-16$ $x=.4428$ $x=.4$ $x=(-60-52.915)/-16$ $x=-112.915/-16$ $x=7.05625$ $x=7.1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.