Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 61

Answer

$x=\dfrac{-1\pm 3i\sqrt{3}}{2}$

Work Step by Step

Using $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ or the Quadratic Formula, the solution/s of the given quadratic equation, $ x^2+x+7=0 ,$ is/are \begin{array}{l}\require{cancel} x=\dfrac{-1\pm\sqrt{1^2-4(1)(7)}}{2(1)} \\\\ x=\dfrac{-1\pm\sqrt{1-28}}{2} \\\\ x=\dfrac{-1\pm\sqrt{-27}}{2} \\\\ x=\dfrac{-1\pm\sqrt{-1}\cdot\sqrt{27}}{2} \\\\ x=\dfrac{-1\pm i\cdot\sqrt{9\cdot3}}{2} \\\\ x=\dfrac{-1\pm i\cdot3\sqrt{3}}{2} \\\\ x=\dfrac{-1\pm 3i\sqrt{3}}{2} .\end{array}
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