Answer
$16xy\sqrt[3]{3y}$
Work Step by Step
Using the properties of radicals, then,
\begin{array}{l}
2\sqrt[3]{24x^3y^4}+4x\sqrt[3]{81y^4}
\\=
2\sqrt[3]{8x^3y^3\cdot3y}+4x\sqrt[3]{27y^3\cdot3y}
\\=
2\cdot2xy\sqrt[3]{3y}+4x\cdot3y\sqrt[3]{3y}
\\=
4xy\sqrt[3]{3y}+12xy\sqrt[3]{3y}
\\=
16xy\sqrt[3]{3y}
.\end{array}