Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 77

Answer

$x-7$

Work Step by Step

Factoring the expressions and then cancelling the common factors between the numerator and the denominator result to \begin{array}{l} \dfrac{2x-14}{2} \\\\= \dfrac{2(x-7)}{2} &\text{ (cancel $2$)} \\\\= x-7 .\end{array}
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