Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 34

Answer

$5 x \sqrt[3] 3$

Work Step by Step

$6\sqrt[3] (24x^{3}) - 2\sqrt[3] (81x^{3}) - x\sqrt[3] 3 $ $= 6\sqrt[3] (3 \times 8 \times x^{3}) - 2\sqrt[3] (3 \times 27 \times x^{3}) - x\sqrt[3] 3 $ $= 6\sqrt[3] (3 \times 2^{3} \times x^{3}) - 2\sqrt[3] (3 \times 3^{3} \times x^{3}) - x\sqrt[3] 3 $ $= 6 \times 2 \times x \sqrt[3] 3 - 2 \times 3 \times x \sqrt[3] 3 - x\sqrt[3] 3 $ $=12x \sqrt[3] 3 -6x \sqrt[3] 3 - x\sqrt[3] 3 $ $=5 x \sqrt[3] 3$
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