Answer
$3x-4$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, then,
\begin{array}{l}
\left( \sqrt[]{3x}+2 \right)\left( \sqrt[]{3x}-2 \right)
\\=
(\sqrt[]{3x})^2-(2)^2
\\=
3x-4
.\end{array}