Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 31

Answer

$6\sqrt[3]{11}-4\sqrt[]{11}$

Work Step by Step

Using the properties of radicals, then, \begin{array}{l} 6\sqrt[3]{11}+8\sqrt[]{11}-12\sqrt[]{11} \\= 6\sqrt[3]{11}+(8\sqrt[]{11}-12\sqrt[]{11}) \\= 6\sqrt[3]{11}-4\sqrt[]{11} .\end{array}
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