Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set - Page 664: 14

Answer

$504$

Work Step by Step

Expand, cancel, and multiply $\frac{9!}{5!\cdot3!} = \frac{9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{5\cdot4\cdot3\cdot2\cdot1\cdot3\cdot2\cdot1} = \frac{9\cdot8\cdot7\cdot6}{3\cdot2\cdot1} = \frac{9\cdot8\cdot7\cdot6}{6} = 9\cdot8\cdot7 = 504$
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