Answer
$-y^9$
Work Step by Step
Using the $(r+1)$st term of the expansion of $(a+b)^n$, which is given by $\dfrac{n!}{(n-r)!r!}a^{n-r}b^r$, then the $
10
$th term of $
(5x-y)^9
$ is
\begin{array}{l}
\dfrac{9!}{0!9!}(5x)^{0}(-y)^{9}
\\\\=
-y^9
\end{array}