Answer
$x^5 + 10 x^4 + 40 x^3 + 80 x^2 + 80 x + 32$
Work Step by Step
Using the Binomial Formula, the expression $
(x+2)^5
$ expands to
\begin{array}{l}
x^52^0+
\dfrac{5}{1!}x^42^1+
\dfrac{5\cdot4}{2!}x^32^2+
\dfrac{5\cdot4\cdot3}{3!}x^22^3+
\dfrac{5\cdot4\cdot3\cdot2}{4!}x^12^4+\\
\dfrac{5\cdot4\cdot3\cdot2\cdot1}{5!}x^02^5
\\\\=
x^5 + 10 x^4 + 40 x^3 + 80 x^2 + 80 x + 32
\end{array}
