Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set - Page 664: 27

Answer

$8 a^3 + 36 a^2 b + 54 a b^2 + 27 b^3$

Work Step by Step

Using the Binomial Formula, the expression $ (2a+3b)^3 $ expands to \begin{array}{l} (2a)^3(3b)^0 \dfrac{3}{1!}(2a)^2(3b)^1+ \dfrac{3\cdot2}{2!}(2a)^1(3b)^2+ \dfrac{3\cdot2\cdot1}{3!}(2a)^0(3b)^3 \\\\= 8 a^3 + 36 a^2 b + 54 a b^2 + 27 b^3 \end{array}
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