## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set: 16

#### Answer

$210$

#### Work Step by Step

Expand, cancel, and multiply $\frac{10!}{4!\cdot6!} = \frac{10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{4\cdot3\cdot2\cdot1\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1} = \frac{10\cdot9\cdot8\cdot7}{4\cdot3\cdot2\cdot1} = 10\cdot3\cdot7 = 210$

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