Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set: 5

Answer

$1,3,9,27,81$

Work Step by Step

The general term $a_n$ of a geometric sequence is given by $a_n = a_1r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio. We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the geometric sequence $a_1 = 1\cdot3^{1-1} = 1\cdot3^0=1\cdot1=1$ $a_2 = 1\cdot3^{2-1} = 1\cdot3^1=1\cdot3=3$ $a_3 = 1\cdot3^{3-1} = 1\cdot3^2=1\cdot9=9$ $a_4 = 1\cdot3^{4-1} = 1\cdot3^3=1\cdot27=27$ $a_5 = 1\cdot3^{5-1} = 1\cdot3^4=1\cdot81=81$
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