Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set: 16

Answer

$a_{13} = 33$

Work Step by Step

Arithmetic sequence: $-3,0,3,...$ $a_{1}= -3$ $d= 0-(-3) = 3$ Using the formula, $a_{n} = a_{1}+(n-1)d$ $a_{13} = -3+(13-1) (3)$ $= -3+(12)(3)$ $= -3+36$ $a_{13} = 33$
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