## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set: 14

#### Answer

$-5120$

#### Work Step by Step

To find the $n$th term of a geometric sequence, we use the formula $a_n = a_1 \cdot r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio. $a_6 = 5\cdot(-4)^{6-1} = 5\cdot(-4)^5 = 5\cdot(-1024) = -5120$

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