Answer
$a_{21}=19$
Work Step by Step
Using $a_n=a_1+(n-1)d$ or the $n$th term of an arithmetic sequence, then,
\begin{array}{l}
a_{21}=14+(21-1)\cdot\dfrac{1}{4}
\\
a_{21}=14+5
\\
a_{21}=19
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 39
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