Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4 - Page 300: 9

Answer

$\dfrac{1}{y^7}$

Work Step by Step

Using $x^{-a}=\dfrac{1}{x^a}$, the given expression, $ y^{-7} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{y^7} .\end{array}
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