Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4 - Page 300: 39

Answer

$8a^2b^2+6ab^2+ab^3+b^3+6ab-5$

Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $ (8a^2b^2-ab+b^3)-(-6ab^2-7ab-ab^3+5) ,$ simplifies to \begin{array}{l}\require{cancel} 8a^2b^2-ab+b^3+6ab^2+7ab+ab^3-5 \\\\= 8a^2b^2+6ab^2+ab^3+b^3+(-ab+7ab)-5 \\\\= 8a^2b^2+6ab^2+ab^3+b^3+6ab-5 .\end{array}
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