Answer
$\dfrac{7}{4}y^2-4y$
Work Step by Step
By combining like terms, the given expression, $
y^2-3y-y+\dfrac{3}{4}y^2
,$ simplifies to
\begin{array}{l}
\left( y^2+\dfrac{3}{4}y^2\right)+(-3y-y)
\\\\=
\dfrac{7}{4}y^2-4y
.\end{array}
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