Answer
$\dfrac{3y^{5}}{x^5}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{9x^3y^2}{3x^8y^{-3}}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{3}\cdot3x^{3-8}y^{2-(-3)}}{\cancel{3}}
\\\\=
3x^{-5}y^{5}
\\\\=
\dfrac{3y^{5}}{x^5}
.\end{array}
