Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4: 7

Answer

$6a^{5}b^{3}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{24a^7b^4}{20a^2b} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4}\cdot6a^{7-2}b^{4-1}}{\cancel{4}\cdot5} \\\\= 6a^{5}b^{3} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.