Answer
$6a^{5}b^{3}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{24a^7b^4}{20a^2b}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{4}\cdot6a^{7-2}b^{4-1}}{\cancel{4}\cdot5}
\\\\=
6a^{5}b^{3}
.\end{array}
