Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 38

Answer

$14a^5-2a^2-a-\frac{2}{3}$

Work Step by Step

Combine like terms to obtain: $=(20a^5-6a^5)-2a^2-a+(\frac{1}{3}-1) \\=14a^5-2a^2-a+(\frac{1}{3}-\frac{3}{3}) \\=14a^5-2a^2-a-\frac{2}{3}$
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