Answer
$\dfrac{1}{16}$
Work Step by Step
Using the laws of exponents, the given expression, $
4^5\cdot 4^{-7}
,$ simplifies to
\begin{array}{l}\require{cancel}
4^{5+(-7)}
\\\\=
4^{-2}
\\\\=
\dfrac{1}{4^{2}}
\\\\=
\dfrac{1}{16}
.\end{array}
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 298: 21
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