Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 25

Answer

$\dfrac{y^3}{8x^3}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{2x}{y} \right)^{-3} ,$ simplifies to \begin{array}{l}\require{cancel} \left( \dfrac{y}{2x} \right)^{3} \\\\= \dfrac{y^3}{2^3x^3} \\\\= \dfrac{y^3}{8x^3} .\end{array}
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