Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 298: 28

Answer

$\color{blue}{2.09 \times 10^4}$

Work Step by Step

Multiply the corresponding parts (multiply the constants together and the powers of 10 together) to obtain: $=(3.8 \times 5.5) \times (10^4 \times 10^{-1}) \\=20.9 \times 10^{4+(-1)} \\=20.9 \times 10^3$ Write $20.9$ as $2.09 \cdot 10^1$ to obtain: $=(2.09\cdot 10^1) \times 10^3 \\=2.09 \times 10^{3+1} \\=\color{blue}{2.09 \times 10^4}$
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