Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 22

Answer

$\dfrac{2b^{9}}{a^{13}}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{6a^{-5}b}{3a^8b^{-8}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{3}\cdot2a^{-5-8}b^{1-(-8)}}{\cancel{3}} \\\\= 2a^{-13}b^{9} \\\\= \dfrac{2b^{9}}{a^{13}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.