Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Mid-Chapter Review - Mixed Review - Page 915: 8

Answer

$n=61$

Work Step by Step

We have to find the position of the term which is equal to $22$ in this arithmetic sequence: $10, 10.2, 10.4, 10.6, . . .$ The common difference $d$ in our case is $d=a_{n+1}-a_n=a_2-a_1=10.2-10=0.2.$. We can find any term of the sequence using the formula $a_n=a_1+d(n-1).$ In our conditions: $a_1=10, d=0.2, a_n=22.$ We have to find $n$. $$22=10+0.2(n-1)=10-0.2+0.2n=9.8+0.2n$$ $$22-9.8=0.2n$$ $$12.2=0.2n$$ $$n=61$$
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