Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Mid-Chapter Review - Mixed Review - Page 915: 6

Answer

$\sum\limits_{k=2}^5k^2=54$

Work Step by Step

We have to write out and evaluate the sum $\sum\limits_{k=2}^5k^2$. Expand the sum: $$\sum\limits_{k=2}^5k^2=2^2+3^2+4^2+5^2.$$ Now we can evaluate it. $$\sum\limits_{k=2}^5k^2=4+9+16+25=9+20+25=45+9=54$$
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