Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Mid-Chapter Review - Mixed Review - Page 915: 4

Answer

$a_n=\frac{1}{n+1}$

Work Step by Step

We are given the sequence: $\frac{1}{2},\frac{1}{3},\frac{1}{4},\frac{1}{5}, . . .$ In order to find the general term we must determine the pattern: $a_1=\frac{1}{2}=\frac{1}{1+1}$ $a_2=\frac{1}{3}=\frac{1}{2+1}$ $a_3=\frac{1}{4}=\frac{1}{3+1}$ $a_4=\frac{1}{5}=\frac{1}{4+1}$ We notice that the general term is a fraction with numerator $1$ and denominator equal to the position of the term in the sequence plus one. The general term $a_n$ will look like $a_n=\dfrac{1}{n+1},$ where $n=1,2,3, . . .$
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