Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Mid-Chapter Review - Mixed Review - Page 915: 3

Answer

$a_{20}=300$

Work Step by Step

We have to find $a_{20}$ if $a_n=n^2-5n$. So we substitute $n=20$ in the general term formula: $a_{20}=20^2-5\cdot20=400-100=300$
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