## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 8, Sequences and Series - Section 8.2 - Arithmetic Sequences - 8.2 Exercises: 8

#### Answer

(a) $a_1=-10$ $a_2=-6$ $a_3=-2$ $a_4=2$ $a_5=6$ (b) $d=4$ (c) Refer to the image below for the graph.

#### Work Step by Step

(a) Find the first five terms of the sequence by substituting 1, 2, 3, 4, and 5 to the given formula to obtain: $a_1=-10+4(1-1)=-10+4(0) = -10+0=-10$ $a_2=-10+4(2-1)=-10+4(1) = -10+4=-6$ $a_3=-10+4(3-1)=-10+4(2) = -10+8=-2$ $a_4=-10+4(4-1)=-10+4(3) = -10+12=2$ $a_5=-10+4(5-1)=-10+4(4) = -10+16=6$ (b) The common difference can be found by subtracting the first term to the second term: $d=-6-(-10) \\d=-6+10 \\d=4$ (c) Plot the points: $(1, -10) \\(2, -6) \\(3, -2) \\(4, 2) \\(5, 6)$ Refer to the attached image in the answer part above.

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