Answer
$a=706\\
a_2=712$
Work Step by Step
RECALL:
The $n^{th}$ $a_n$ of an arithmetic sequence is given by the formula:
$a_n = a + d(n-1)$
where
$a$ = first term
$d$ = common difference
The 50th term is 1000. Thus, $a_{50} = 1000$ and the common difference is $d=6$.
Substitute these values to the formula above to obtain:
$a_n = a + d(n-1)
\\a_{50} = a + d(50-1)
\\1000 = a + 6(49)
\\1000 = a + 294
\\1000-294= a
\\706 = a$
The second term can be found by adding the common difference to the first term.
Thus,
$a_2=706+6
\\a_2=712$
Therefore the first two terms of the sequence are:
$a=706\\
a_2=712$
