## College Algebra 7th Edition

(a) $a_1=-10$ $a_2=10$ $a_3=30$ $a_4=50$ $a_5=70$ (b) $d=20$ (c) Refer to the image below for the graph.
(a) Find the first five terms of the sequence by substituting 1, 2, 3, 4, and 5 to the given formula to obtain: $a_1=-10+20(1-1) = -10+20(0) = -10+0=-10$ $a_2=-10+20(2-1) = -10+20(1) = -10+20=10$ $a_3=-10+20(3-1) = -10+20(2) = -10+40=30$ $a_4=-10+20(4-1) = -10+20(3) = -10+60=50$ $a_5=-10+20(5-1) = -10+20(4) = -10+80=70$ (b) The common difference can be found by subtracting the first term to the second term: $d=10-(-10) \\d=10+10 \\d=20$ (c) Plot the points: $(1, -10) \\(2, 10) \\(3, 30) \\(4. 50) \\(5, 70)$ Refer to the attached image in the answer part above.