College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.2 - Arithmetic Sequences - 8.2 Exercises: 71

Answer

$\$1250$

Work Step by Step

We know that the value of the computer starts at: $a_1=12500$ And decreases by $\$1875/year$, so: $d=-1875$ To find the value after $6$ years, we use $n=7$ (the value on the 7th year, after 6 years have passed): $a_n=a_1+(n-1)d$ $a_7=12500+(7-1)*-1875$ $a_7=1250$
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