Chapter 8, Sequences and Series - Section 8.2 - Arithmetic Sequences - 8.2 Exercises - Page 607: 71

$\$1250$

We know that the value of the computer starts at: $a_1=12500$ And decreases by $\$1875/year$, so: $d=-1875$ To find the value after $6$ years, we use $n=7$ (the value on the 7th year, after 6 years have passed): $a_n=a_1+(n-1)d$ $a_7=12500+(7-1)*-1875$ $a_7=1250$