## College Algebra 7th Edition

$d=-2.7$ $a_5=4.2$ The $n^{th}$ term is given by: $a_n=15-2.7(n-1)$ $a_{100} = -252.3$
The sequence is arithmetic so the terms have a common difference. The common difference $d$ can be found by subtracting any term to the next term in the sequence. Thus, $d=12.3-15 \\d=-2.7$ The fifth term $a_5$ can be found by adding the common difference $-2.7$ to the fourth term. The fourth term of the sequence is $6.9$. Thus, $a_5 = 6.9+(-2.7) \\a_5=4.2$ The $n^{th}$ term $a_n$ of an arithmetic sequence is given by the formula $a_n = a+d(n-1)$ where $a$ = first term and $d$ = common difference. The sequence has $a=15$ and $d=-2.7$. Thus, the $n^{th}$ term is given by: $a_n = 15+(-2.7)(n-1) \\a_n=15-2.7(n-1)$ Substituting 100 to $n$ gives the 100th term as: $a_{100} = 15-2.7(100-1) \\a_{100} = 15-2.7(99) \\a_{100} = 15-267.3 \\a_{100} = -252.3$