College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises: 30

Answer

$\frac{1}{2}(\ln a+\ln b)=\frac{1}{2}\ln a+\frac{1}{2}\ln b$

Work Step by Step

$\ln\sqrt{ab}=\ln(ab)^{1/2}=\frac{1}{2}\ln ab=\frac{1}{2}(\ln a+\ln b)=\frac{1}{2}\ln a+\frac{1}{2}\ln b$
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